Base | Representation |
---|---|
bin | 10011100110100001111110… |
… | …01100011111010011111011 |
3 | 12122121211110002121110221022 |
4 | 21303100333030133103323 |
5 | 21122214230104134433 |
6 | 231402154135133055 |
7 | 12036154543516601 |
oct | 1163207714372373 |
9 | 178554402543838 |
10 | 43105352021243 |
11 | 128099715096a6 |
12 | 4a0213321418b |
13 | 1b08a81678b75 |
14 | a9044b169871 |
15 | 4eb408489698 |
hex | 27343f31f4fb |
43105352021243 has 4 divisors (see below), whose sum is σ = 43106140583640. Its totient is φ = 43104563458848.
The previous prime is 43105352021143. The next prime is 43105352021269. The reversal of 43105352021243 is 34212025350134.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43105352021243 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43105352021143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 394199198 + ... + 394308531.
It is an arithmetic number, because the mean of its divisors is an integer number (10776535145910).
Almost surely, 243105352021243 is an apocalyptic number.
43105352021243 is a deficient number, since it is larger than the sum of its proper divisors (788562397).
43105352021243 is an equidigital number, since it uses as much as digits as its factorization.
43105352021243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 788562396.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 43105352021243 its reverse (34212025350134), we get a palindrome (77317377371377).
The spelling of 43105352021243 in words is "forty-three trillion, one hundred five billion, three hundred fifty-two million, twenty-one thousand, two hundred forty-three".
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