43121130000131 has 4 divisors (see below), whose sum is σ = 43155654525000. Its totient is φ = 43086605475264.

The previous prime is 43121130000107. The next prime is 43121130000133. The reversal of 43121130000131 is 13100003112134.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 43121130000131 - 2¹⁴ = 43121129983747 is a prime.

It is a super-2 number, since 2×43121130000131² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43121130000133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17262260561 + ... + 17262263058.

It is an arithmetic number, because the mean of its divisors is an integer number (10788913631250).

Almost surely, 2^{43121130000131} is an apocalyptic number.

43121130000131 is a deficient number, since it is larger than the sum of its proper divisors (34524524869).

43121130000131 is a wasteful number, since it uses less digits than its factorization.

43121130000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34524524868.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 43121130000131 its reverse (13100003112134), we get a palindrome (56221133112265).

The spelling of 43121130000131 in words is "forty-three trillion, one hundred twenty-one billion, one hundred thirty million, one hundred thirty-one", and thus it is an aban number.