Base | Representation |
---|---|
bin | 10011100110111111010111… |
… | …11000111010110000011011 |
3 | 12122200100011222122211011122 |
4 | 21303133223320322300123 |
5 | 21122444040332013120 |
6 | 231413324155115455 |
7 | 12040253622331421 |
oct | 1163375370726033 |
9 | 178610158584148 |
10 | 43121134251035 |
11 | 12815630134515 |
12 | 4a051b8742b8b |
13 | 1b0a3c8295589 |
14 | a91107211111 |
15 | 4eba2dcb5a25 |
hex | 2737ebe3ac1b |
43121134251035 has 16 divisors (see below), whose sum is σ = 52250728071360. Its totient is φ = 34160034355200.
The previous prime is 43121134251031. The next prime is 43121134251037. The reversal of 43121134251035 is 53015243112134.
It is not a de Polignac number, because 43121134251035 - 22 = 43121134251031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 43121134250986 and 43121134251004.
It is not an unprimeable number, because it can be changed into a prime (43121134251031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6665135 + ... + 11430935.
It is an arithmetic number, because the mean of its divisors is an integer number (3265670504460).
Almost surely, 243121134251035 is an apocalyptic number.
43121134251035 is a deficient number, since it is larger than the sum of its proper divisors (9129593820325).
43121134251035 is a wasteful number, since it uses less digits than its factorization.
43121134251035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4783478.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 43121134251035 its reverse (53015243112134), we get a palindrome (96136377363169).
The spelling of 43121134251035 in words is "forty-three trillion, one hundred twenty-one billion, one hundred thirty-four million, two hundred fifty-one thousand, thirty-five".
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