Base | Representation |
---|---|
bin | 111110110000000101100… |
… | …111011000000111001001 |
3 | 120021020122111220221102012 |
4 | 332300011213120013021 |
5 | 1031122432242424031 |
6 | 13101003310145305 |
7 | 623356234615445 |
oct | 76600547300711 |
9 | 16236574827365 |
10 | 4312241373641 |
11 | 14128a1921093 |
12 | 5978a8ab2235 |
13 | 253847aa0ca6 |
14 | 10c9dc171825 |
15 | 772881b7b2b |
hex | 3ec059d81c9 |
4312241373641 has 16 divisors (see below), whose sum is σ = 4583161105344. Its totient is φ = 4043246298624.
The previous prime is 4312241373631. The next prime is 4312241373659. The reversal of 4312241373641 is 1463731422134.
It is a cyclic number.
It is not a de Polignac number, because 4312241373641 - 214 = 4312241357257 is a prime.
It is a super-3 number, since 3×43122413736413 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4312241373631) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19872170 + ... + 20087996.
It is an arithmetic number, because the mean of its divisors is an integer number (286447569084).
Almost surely, 24312241373641 is an apocalyptic number.
It is an amenable number.
4312241373641 is a deficient number, since it is larger than the sum of its proper divisors (270919731703).
4312241373641 is a wasteful number, since it uses less digits than its factorization.
4312241373641 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 220280.
The product of its digits is 290304, while the sum is 41.
Adding to 4312241373641 its reverse (1463731422134), we get a palindrome (5775972795775).
The spelling of 4312241373641 in words is "four trillion, three hundred twelve billion, two hundred forty-one million, three hundred seventy-three thousand, six hundred forty-one".
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