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431232443152225 = 521113678990722303
BaseRepresentation
bin110001000001101000010000…
…0100101101111011101100001
32002112212102022102011212202221
41202003100200211233131201
5423010303020421332400
64125053241032111041
7156555341642304331
oct14203204045573541
92075772272155687
10431232443152225
11115449719a53240
12404478a0835481
1315681077853ca0
14786ba93c1b0c1
1534cc52ae68c1a
hex188342096f761

431232443152225 has 192 divisors, whose sum is σ = 645492205854720. Its totient is φ = 281650066790400.

The previous prime is 431232443152219. The next prime is 431232443152271. The reversal of 431232443152225 is 522251344232134.

It is not a de Polignac number, because 431232443152225 - 217 = 431232443021153 is a prime.

It is a super-3 number, since 3×4312324431522253 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 19335165424 + ... + 19335187726.

It is an arithmetic number, because the mean of its divisors is an integer number (3361938572160).

Almost surely, 2431232443152225 is an apocalyptic number.

It is an amenable number.

431232443152225 is a deficient number, since it is larger than the sum of its proper divisors (214259762702495).

431232443152225 is a wasteful number, since it uses less digits than its factorization.

431232443152225 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23400 (or 23395 counting only the distinct ones).

The product of its digits is 1382400, while the sum is 43.

Adding to 431232443152225 its reverse (522251344232134), we get a palindrome (953483787384359).

The spelling of 431232443152225 in words is "four hundred thirty-one trillion, two hundred thirty-two billion, four hundred forty-three million, one hundred fifty-two thousand, two hundred twenty-five".