Base | Representation |
---|---|
bin | 101000001010011110… |
… | …010110101100100001 |
3 | 11010022111001102120222 |
4 | 220022132112230201 |
5 | 1201310100334101 |
6 | 31451143012425 |
7 | 3054454605104 |
oct | 501236265441 |
9 | 133274042528 |
10 | 43125402401 |
11 | 17320190134 |
12 | 843673a115 |
13 | 40b37329b3 |
14 | 21316d873b |
15 | 11c609c01b |
hex | a0a796b21 |
43125402401 has 4 divisors (see below), whose sum is σ = 43716161412. Its totient is φ = 42534643392.
The previous prime is 43125402347. The next prime is 43125402407. The reversal of 43125402401 is 10420452134.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 14544118801 + 28581283600 = 120599^2 + 169060^2 .
It is a cyclic number.
It is not a de Polignac number, because 43125402401 - 210 = 43125401377 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43125402407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 295379396 + ... + 295379541.
It is an arithmetic number, because the mean of its divisors is an integer number (10929040353).
Almost surely, 243125402401 is an apocalyptic number.
It is an amenable number.
43125402401 is a deficient number, since it is larger than the sum of its proper divisors (590759011).
43125402401 is an equidigital number, since it uses as much as digits as its factorization.
43125402401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 590759010.
The product of its (nonzero) digits is 3840, while the sum is 26.
Adding to 43125402401 its reverse (10420452134), we get a palindrome (53545854535).
The spelling of 43125402401 in words is "forty-three billion, one hundred twenty-five million, four hundred two thousand, four hundred one".
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