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43131000131 = 89484617979
BaseRepresentation
bin101000001010110011…
…101101010101000011
311010022212120211020022
4220022303231111003
51201313014001011
631451503004055
73054553311032
oct501263552503
9133285524208
1043131000131
111732336385a
12843859962b
1340b494286b
142132354719
1511c68058db
hexa0aced543

43131000131 has 4 divisors (see below), whose sum is σ = 43615618200. Its totient is φ = 42646382064.

The previous prime is 43131000097. The next prime is 43131000137. The reversal of 43131000131 is 13100013134.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43131000131 is a prime.

It is a super-2 number, since 2×431310001312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43131000137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242308901 + ... + 242309078.

It is an arithmetic number, because the mean of its divisors is an integer number (10903904550).

Almost surely, 243131000131 is an apocalyptic number.

43131000131 is a deficient number, since it is larger than the sum of its proper divisors (484618069).

43131000131 is an equidigital number, since it uses as much as digits as its factorization.

43131000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 484618068.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 43131000131 its reverse (13100013134), we get a palindrome (56231013265).

The spelling of 43131000131 in words is "forty-three billion, one hundred thirty-one million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 89 484617979 43131000131