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43131113121 = 314377037707
BaseRepresentation
bin101000001010110100…
…001000111010100001
311010022212210120020010
4220022310020322201
51201313031104441
631451505235133
73054554261325
oct501264107241
9133285716203
1043131113121
1117323430738
128438632aa9
1340b4982115
142132383985
1511c6829116
hexa0ad08ea1

43131113121 has 4 divisors (see below), whose sum is σ = 57508150832. Its totient is φ = 28754075412.

The previous prime is 43131113093. The next prime is 43131113131. The reversal of 43131113121 is 12131113134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 43131113121 - 25 = 43131113089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43131113131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7188518851 + ... + 7188518856.

It is an arithmetic number, because the mean of its divisors is an integer number (14377037708).

Almost surely, 243131113121 is an apocalyptic number.

It is an amenable number.

43131113121 is a deficient number, since it is larger than the sum of its proper divisors (14377037711).

43131113121 is a wasteful number, since it uses less digits than its factorization.

43131113121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14377037710.

The product of its digits is 216, while the sum is 21.

Adding to 43131113121 its reverse (12131113134), we get a palindrome (55262226255).

The spelling of 43131113121 in words is "forty-three billion, one hundred thirty-one million, one hundred thirteen thousand, one hundred twenty-one".

Divisors: 1 3 14377037707 43131113121