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4313520130043 = 6196973999923
BaseRepresentation
bin111110110001010001110…
…101011100011111111011
3120021100221122010111102102
4332301101311130133323
51031133042123130133
613101334230254015
7623433023100305
oct76612165343773
916240848114372
104313520130043
111413398729763
12597ba51b730b
132539bc9ab797
1410cabdd22975
15773105ad7e8
hex3ec51d5c7fb

4313520130043 has 8 divisors (see below), whose sum is σ = 4320593851200. Its totient is φ = 4306446749448.

The previous prime is 4313520130039. The next prime is 4313520130103. The reversal of 4313520130043 is 3400310253134.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4313520130043 - 22 = 4313520130039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4313520129988 and 4313520130015.

It is not an unprimeable number, because it can be changed into a prime (4313520130343) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43118480 + ... + 43218402.

It is an arithmetic number, because the mean of its divisors is an integer number (540074231400).

Almost surely, 24313520130043 is an apocalyptic number.

4313520130043 is a deficient number, since it is larger than the sum of its proper divisors (7073721157).

4313520130043 is an equidigital number, since it uses as much as digits as its factorization.

4313520130043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 170281.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 4313520130043 its reverse (3400310253134), we get a palindrome (7713830383177).

The spelling of 4313520130043 in words is "four trillion, three hundred thirteen billion, five hundred twenty million, one hundred thirty thousand, forty-three".

Divisors: 1 619 69739 99923 43168441 61852337 6968530097 4313520130043