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4314100201403 = 19227057905337
BaseRepresentation
bin111110110001110100011…
…010001111011110111011
3120021102110001122011201212
4332301310122033132323
51031140234122421103
613101511551233335
7623453265445406
oct76616432173673
916242401564655
104314100201403
111413666105983
1259812751884b
13253a82c1a585
1410cb36d9cd3d
15773464917d8
hex3ec7468f7bb

4314100201403 has 4 divisors (see below), whose sum is σ = 4541158106760. Its totient is φ = 4087042296048.

The previous prime is 4314100201393. The next prime is 4314100201429. The reversal of 4314100201403 is 3041020014134.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4314100201403 - 24 = 4314100201387 is a prime.

It is a super-3 number, since 3×43141002014033 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4314100209403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113528952650 + ... + 113528952687.

It is an arithmetic number, because the mean of its divisors is an integer number (1135289526690).

Almost surely, 24314100201403 is an apocalyptic number.

4314100201403 is a deficient number, since it is larger than the sum of its proper divisors (227057905357).

4314100201403 is a wasteful number, since it uses less digits than its factorization.

4314100201403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 227057905356.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 4314100201403 its reverse (3041020014134), we get a palindrome (7355120215537).

The spelling of 4314100201403 in words is "four trillion, three hundred fourteen billion, one hundred million, two hundred one thousand, four hundred three".

Divisors: 1 19 227057905337 4314100201403