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43142035 = 58628407
BaseRepresentation
bin1010010010010…
…0101110010011
310000011211202011
42210210232103
542021021120
64140403351
71032462346
oct244445623
9100154664
1043142035
1122397282
1212546557
138c26a41
145a3045d
153bc2c5a
hex2924b93

43142035 has 4 divisors (see below), whose sum is σ = 51770448. Its totient is φ = 34513624.

The previous prime is 43142017. The next prime is 43142063. The reversal of 43142035 is 53024134.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 43142035 - 25 = 43142003 is a prime.

It is a super-2 number, since 2×431420352 = 3722470367882450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43141997 and 43142015.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4314199 + ... + 4314208.

It is an arithmetic number, because the mean of its divisors is an integer number (12942612).

Almost surely, 243142035 is an apocalyptic number.

43142035 is a deficient number, since it is larger than the sum of its proper divisors (8628413).

43142035 is an equidigital number, since it uses as much as digits as its factorization.

43142035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8628412.

The product of its (nonzero) digits is 1440, while the sum is 22.

The square root of 43142035 is about 6568.2596629549. The cubic root of 43142035 is about 350.7251225195.

Adding to 43142035 its reverse (53024134), we get a palindrome (96166169).

The spelling of 43142035 in words is "forty-three million, one hundred forty-two thousand, thirty-five".

Divisors: 1 5 8628407 43142035