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4314320012251 = 19227069474329
BaseRepresentation
bin111110110010000001100…
…000110000001111011011
3120021110000101020201112101
4332302001200300033123
51031141211410343001
613101545442424231
7623461605013354
oct76620140601733
916243011221471
104314320012251
11141376919a037
12598189062077
13253ab961cb72
1410cb5825ad2b
157735a910a01
hex3ec818303db

4314320012251 has 4 divisors (see below), whose sum is σ = 4541389486600. Its totient is φ = 4087250537904.

The previous prime is 4314320012237. The next prime is 4314320012273. The reversal of 4314320012251 is 1522100234134.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4314320012251 is a prime.

It is a super-2 number, since 2×43143200122512 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4314320015251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113534737146 + ... + 113534737183.

It is an arithmetic number, because the mean of its divisors is an integer number (1135347371650).

Almost surely, 24314320012251 is an apocalyptic number.

4314320012251 is a deficient number, since it is larger than the sum of its proper divisors (227069474349).

4314320012251 is a wasteful number, since it uses less digits than its factorization.

4314320012251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 227069474348.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 4314320012251 its reverse (1522100234134), we get a palindrome (5836420246385).

The spelling of 4314320012251 in words is "four trillion, three hundred fourteen billion, three hundred twenty million, twelve thousand, two hundred fifty-one".

Divisors: 1 19 227069474329 4314320012251