Base | Representation |
---|---|
bin | 10011100111101000101100… |
… | …11001010001110000011001 |
3 | 12122202110110022020002112120 |
4 | 21303310112121101300121 |
5 | 21123330010441312101 |
6 | 231431434004131453 |
7 | 12042000513030354 |
oct | 1163642631216031 |
9 | 178673408202476 |
10 | 43143322213401 |
11 | 12823a86710aa3 |
12 | 4a0956b396b89 |
13 | 1b0c5230486a7 |
14 | a9220dd1d29b |
15 | 4ec3cbb71b36 |
hex | 273d16651c19 |
43143322213401 has 8 divisors (see below), whose sum is σ = 57564074302944. Its totient is φ = 28742392466400.
The previous prime is 43143322213349. The next prime is 43143322213423. The reversal of 43143322213401 is 10431222334134.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 43143322213401 - 27 = 43143322213273 is a prime.
It is a super-2 number, since 2×431433222134012 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (43143322223401) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4955580556 + ... + 4955589261.
It is an arithmetic number, because the mean of its divisors is an integer number (7195509287868).
Almost surely, 243143322213401 is an apocalyptic number.
It is an amenable number.
43143322213401 is a deficient number, since it is larger than the sum of its proper divisors (14420752089543).
43143322213401 is a wasteful number, since it uses less digits than its factorization.
43143322213401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9911171271.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 43143322213401 its reverse (10431222334134), we get a palindrome (53574544547535).
The spelling of 43143322213401 in words is "forty-three trillion, one hundred forty-three billion, three hundred twenty-two million, two hundred thirteen thousand, four hundred one".
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