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43149412081 = 211120440271
BaseRepresentation
bin101000001011111001…
…111100011011110001
311010101011020020200101
4220023321330123301
51201332222141311
631453401352401
73055165644136
oct501371743361
9133334206611
1043149412081
1117332799a46
128442798701
1340b86bb1c9
14213498858d
1511c8240ec1
hexa0be7c6f1

43149412081 has 4 divisors (see below), whose sum is σ = 43169854464. Its totient is φ = 43128969700.

The previous prime is 43149412073. The next prime is 43149412109. The reversal of 43149412081 is 18021494134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43149412081 - 23 = 43149412073 is a prime.

It is a super-2 number, since 2×431494120812 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 43149412081.

It is not an unprimeable number, because it can be changed into a prime (43149412381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10218025 + ... + 10222246.

It is an arithmetic number, because the mean of its divisors is an integer number (10792463616).

Almost surely, 243149412081 is an apocalyptic number.

It is an amenable number.

43149412081 is a deficient number, since it is larger than the sum of its proper divisors (20442383).

43149412081 is a wasteful number, since it uses less digits than its factorization.

43149412081 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20442382.

The product of its (nonzero) digits is 27648, while the sum is 37.

The spelling of 43149412081 in words is "forty-three billion, one hundred forty-nine million, four hundred twelve thousand, eighty-one".

Divisors: 1 2111 20440271 43149412081