Base | Representation |
---|---|
bin | 10011101001010010011110… |
… | …11001110110101110110011 |
3 | 12122221220001011120012201112 |
4 | 21310221033121312232303 |
5 | 21130242312442203021 |
6 | 231513505201023535 |
7 | 12046051035555416 |
oct | 1164511731665663 |
9 | 178856034505645 |
10 | 43200113241011 |
11 | 12846079777661 |
12 | 4a1857a624bab |
13 | 1b149a3a1513c |
14 | a94c7a52db7d |
15 | 4edb02802d5b |
hex | 274a4f676bb3 |
43200113241011 has 4 divisors (see below), whose sum is σ = 43200501804024. Its totient is φ = 43199724678000.
The previous prime is 43200113240939. The next prime is 43200113241041. The reversal of 43200113241011 is 11014231100234.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43200113241011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43200113241041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 194114690 + ... + 194337111.
It is an arithmetic number, because the mean of its divisors is an integer number (10800125451006).
Almost surely, 243200113241011 is an apocalyptic number.
43200113241011 is a deficient number, since it is larger than the sum of its proper divisors (388563013).
43200113241011 is a wasteful number, since it uses less digits than its factorization.
43200113241011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 388563012.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 43200113241011 its reverse (11014231100234), we get a palindrome (54214344341245).
The spelling of 43200113241011 in words is "forty-three trillion, two hundred billion, one hundred thirteen million, two hundred forty-one thousand, eleven".
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