Base | Representation |
---|---|
bin | 1100100101011011101… |
… | …00101100001010011001 |
3 | 1112100010121100101120002 |
4 | 12102231310230022121 |
5 | 24041040212002340 |
6 | 530351531142345 |
7 | 43145411600204 |
oct | 6225564541231 |
9 | 1470117311502 |
10 | 432413000345 |
11 | 157426958297 |
12 | 6b97a2a49b5 |
13 | 31a128c14a1 |
14 | 16d00c9293b |
15 | b3ac2b5715 |
hex | 64add2c299 |
432413000345 has 8 divisors (see below), whose sum is σ = 531551590920. Its totient is φ = 337493073280.
The previous prime is 432413000323. The next prime is 432413000347. The reversal of 432413000345 is 543000314234.
It can be written as a sum of positive squares in 4 ways, for example, as 2612129881 + 429800870464 = 51109^2 + 655592^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 432413000345 - 218 = 432412738201 is a prime.
It is not an unprimeable number, because it can be changed into a prime (432413000347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1054665650 + ... + 1054666059.
It is an arithmetic number, because the mean of its divisors is an integer number (66443948865).
Almost surely, 2432413000345 is an apocalyptic number.
It is an amenable number.
432413000345 is a deficient number, since it is larger than the sum of its proper divisors (99138590575).
432413000345 is a wasteful number, since it uses less digits than its factorization.
432413000345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2109331755.
The product of its (nonzero) digits is 17280, while the sum is 29.
Adding to 432413000345 its reverse (543000314234), we get a palindrome (975413314579).
The spelling of 432413000345 in words is "four hundred thirty-two billion, four hundred thirteen million, three hundred forty-five", and thus it is an aban number.
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