Base | Representation |
---|---|
bin | 10011101010100000100111… |
… | …01110010001101001010011 |
3 | 12200002220022121212101010011 |
4 | 21311100103232101221103 |
5 | 21131434220234243011 |
6 | 231545043500415351 |
7 | 12052064412201553 |
oct | 1165202356215123 |
9 | 180086277771104 |
10 | 43242061634131 |
11 | 12861945524248 |
12 | 4a24726b47557 |
13 | 1b1892a643129 |
14 | a96cd97a1163 |
15 | 4eec5a3a6621 |
hex | 275413b91a53 |
43242061634131 has 4 divisors (see below), whose sum is σ = 43307480790064. Its totient is φ = 43176642478200.
The previous prime is 43242061634063. The next prime is 43242061634159. The reversal of 43242061634131 is 13143616024234.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 43242061634131 - 219 = 43242061109843 is a prime.
It is a super-2 number, since 2×432420616341312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43242061634731) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32709576975 + ... + 32709578296.
It is an arithmetic number, because the mean of its divisors is an integer number (10826870197516).
Almost surely, 243242061634131 is an apocalyptic number.
43242061634131 is a deficient number, since it is larger than the sum of its proper divisors (65419155933).
43242061634131 is an equidigital number, since it uses as much as digits as its factorization.
43242061634131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65419155932.
The product of its (nonzero) digits is 248832, while the sum is 40.
Adding to 43242061634131 its reverse (13143616024234), we get a palindrome (56385677658365).
The spelling of 43242061634131 in words is "forty-three trillion, two hundred forty-two billion, sixty-one million, six hundred thirty-four thousand, one hundred thirty-one".
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