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43301140041 = 314433713347
BaseRepresentation
bin101000010100111100…
…101111011001001001
311010202201201211022110
4220110330233121021
51202140042440131
631520421412533
73062020421535
oct502474573111
9133681654273
1043301140041
1117400401455
12848556a149
134110c73773
14214aba2bc5
1511d6712646
hexa14f2f649

43301140041 has 4 divisors (see below), whose sum is σ = 57734853392. Its totient is φ = 28867426692.

The previous prime is 43301140037. The next prime is 43301140097. The reversal of 43301140041 is 14004110334.

43301140041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 43301140041 - 22 = 43301140037 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43301140031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7216856671 + ... + 7216856676.

It is an arithmetic number, because the mean of its divisors is an integer number (14433713348).

Almost surely, 243301140041 is an apocalyptic number.

It is an amenable number.

43301140041 is a deficient number, since it is larger than the sum of its proper divisors (14433713351).

43301140041 is a wasteful number, since it uses less digits than its factorization.

43301140041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14433713350.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 43301140041 its reverse (14004110334), we get a palindrome (57305250375).

The spelling of 43301140041 in words is "forty-three billion, three hundred one million, one hundred forty thousand, forty-one".

Divisors: 1 3 14433713347 43301140041