Base | Representation |
---|---|
bin | 111111000001101100000… |
… | …011111010101010010011 |
3 | 120100001102121000122121112 |
4 | 333001230003322222103 |
5 | 1031430133320003103 |
6 | 13113410453243535 |
7 | 624625454366606 |
oct | 77015403725223 |
9 | 16301377018545 |
10 | 4331140000403 |
11 | 141a90a688097 |
12 | 59b4a20335ab |
13 | 25556a236b88 |
14 | 10d8b207c33d |
15 | 779e23cacd8 |
hex | 3f06c0faa93 |
4331140000403 has 4 divisors (see below), whose sum is σ = 4371617944440. Its totient is φ = 4290662056368.
The previous prime is 4331140000399. The next prime is 4331140000433. The reversal of 4331140000403 is 3040000411334.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4331140000403 - 22 = 4331140000399 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4331140000433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20238971858 + ... + 20238972071.
It is an arithmetic number, because the mean of its divisors is an integer number (1092904486110).
Almost surely, 24331140000403 is an apocalyptic number.
4331140000403 is a deficient number, since it is larger than the sum of its proper divisors (40477944037).
4331140000403 is a wasteful number, since it uses less digits than its factorization.
4331140000403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40477944036.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 4331140000403 its reverse (3040000411334), we get a palindrome (7371140411737).
The spelling of 4331140000403 in words is "four trillion, three hundred thirty-one billion, one hundred forty million, four hundred three", and thus it is an aban number.
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