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43312121041 = 76187445863
BaseRepresentation
bin101000010101100110…
…101000010011010001
311010210111101201102011
4220111212220103101
51202200400333131
631521453022521
73062212645240
oct502546502321
9133714351364
1043312121041
1117406621662
128489184a41
1341133199b7
14214c420957
1511d76810b1
hexa159a84d1

43312121041 has 4 divisors (see below), whose sum is σ = 49499566912. Its totient is φ = 37124675172.

The previous prime is 43312121033. The next prime is 43312121057. The reversal of 43312121041 is 14012121334.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43312121041 - 23 = 43312121033 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43312121011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3093722925 + ... + 3093722938.

It is an arithmetic number, because the mean of its divisors is an integer number (12374891728).

Almost surely, 243312121041 is an apocalyptic number.

It is an amenable number.

43312121041 is a deficient number, since it is larger than the sum of its proper divisors (6187445871).

43312121041 is an equidigital number, since it uses as much as digits as its factorization.

43312121041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6187445870.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 43312121041 its reverse (14012121334), we get a palindrome (57324242375).

The spelling of 43312121041 in words is "forty-three billion, three hundred twelve million, one hundred twenty-one thousand, forty-one".

Divisors: 1 7 6187445863 43312121041