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43312130201 = 139311598059
BaseRepresentation
bin101000010101100110…
…101010100010011001
311010210111102011222102
4220111212222202121
51202200401131301
631521453133145
73062213014034
oct502546524231
9133714364872
1043312130201
111740662852a
12848918a1b5
134113320c12
14214c42401b
1511d7683b6b
hexa159aa899

43312130201 has 4 divisors (see below), whose sum is σ = 43623728400. Its totient is φ = 43000532004.

The previous prime is 43312130117. The next prime is 43312130203. The reversal of 43312130201 is 10203121334.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43312130201 - 210 = 43312129177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43312130203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155798891 + ... + 155799168.

It is an arithmetic number, because the mean of its divisors is an integer number (10905932100).

Almost surely, 243312130201 is an apocalyptic number.

It is an amenable number.

43312130201 is a deficient number, since it is larger than the sum of its proper divisors (311598199).

43312130201 is a wasteful number, since it uses less digits than its factorization.

43312130201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 311598198.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 43312130201 its reverse (10203121334), we get a palindrome (53515251535).

The spelling of 43312130201 in words is "forty-three billion, three hundred twelve million, one hundred thirty thousand, two hundred one".

Divisors: 1 139 311598059 43312130201