Base | Representation |
---|---|
bin | 111111000001110010001… |
… | …010010100111111010011 |
3 | 120100001200201121021012001 |
4 | 333001302022110333103 |
5 | 1031430341020010103 |
6 | 13113424551014431 |
7 | 624631136323612 |
oct | 77016212247723 |
9 | 16301621537161 |
10 | 4331242344403 |
11 | 141a96242a707 |
12 | 59b51036a417 |
13 | 2555854bb560 |
14 | 10d8c18bd879 |
15 | 779eb39501d |
hex | 3f072294fd3 |
4331242344403 has 4 divisors (see below), whose sum is σ = 4664414832448. Its totient is φ = 3998069856360.
The previous prime is 4331242344389. The next prime is 4331242344431. The reversal of 4331242344403 is 3044432421334.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4331242344403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4331242344203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166586244003 + ... + 166586244028.
It is an arithmetic number, because the mean of its divisors is an integer number (1166103708112).
Almost surely, 24331242344403 is an apocalyptic number.
4331242344403 is a deficient number, since it is larger than the sum of its proper divisors (333172488045).
4331242344403 is a wasteful number, since it uses less digits than its factorization.
4331242344403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 333172488044.
The product of its (nonzero) digits is 331776, while the sum is 37.
Adding to 4331242344403 its reverse (3044432421334), we get a palindrome (7375674765737).
The spelling of 4331242344403 in words is "four trillion, three hundred thirty-one billion, two hundred forty-two million, three hundred forty-four thousand, four hundred three".
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