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4331242344403 = 13333172488031
BaseRepresentation
bin111111000001110010001…
…010010100111111010011
3120100001200201121021012001
4333001302022110333103
51031430341020010103
613113424551014431
7624631136323612
oct77016212247723
916301621537161
104331242344403
11141a96242a707
1259b51036a417
132555854bb560
1410d8c18bd879
15779eb39501d
hex3f072294fd3

4331242344403 has 4 divisors (see below), whose sum is σ = 4664414832448. Its totient is φ = 3998069856360.

The previous prime is 4331242344389. The next prime is 4331242344431. The reversal of 4331242344403 is 3044432421334.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4331242344403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4331242344203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166586244003 + ... + 166586244028.

It is an arithmetic number, because the mean of its divisors is an integer number (1166103708112).

Almost surely, 24331242344403 is an apocalyptic number.

4331242344403 is a deficient number, since it is larger than the sum of its proper divisors (333172488045).

4331242344403 is a wasteful number, since it uses less digits than its factorization.

4331242344403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 333172488044.

The product of its (nonzero) digits is 331776, while the sum is 37.

Adding to 4331242344403 its reverse (3044432421334), we get a palindrome (7375674765737).

The spelling of 4331242344403 in words is "four trillion, three hundred thirty-one billion, two hundred forty-two million, three hundred forty-four thousand, four hundred three".

Divisors: 1 13 333172488031 4331242344403