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4331320011305 = 5732525551027
BaseRepresentation
bin111111000001110110110…
…010100110101000101001
3120100001220010202011010222
4333001312302212220221
51031431020410330210
613113440403415425
7624633101432000
oct77016662465051
916301803664128
104331320011305
11141a9a2257a31
1259b532384575
132555986129c1
1410d8cbd39c37
1577a030d7655
hex3f076ca6a29

4331320011305 has 16 divisors (see below), whose sum is σ = 6061322467200. Its totient is φ = 2970048006576.

The previous prime is 4331320011269. The next prime is 4331320011313. The reversal of 4331320011305 is 5031100231334.

It is a de Polignac number, because none of the positive numbers 2k-4331320011305 is a prime.

It is a super-2 number, since 2×43313200113052 (a number of 26 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1262773799 + ... + 1262777228.

It is an arithmetic number, because the mean of its divisors is an integer number (378832654200).

Almost surely, 24331320011305 is an apocalyptic number.

It is an amenable number.

4331320011305 is a deficient number, since it is larger than the sum of its proper divisors (1730002455895).

4331320011305 is an equidigital number, since it uses as much as digits as its factorization.

4331320011305 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2525551053 (or 2525551039 counting only the distinct ones).

The product of its (nonzero) digits is 3240, while the sum is 26.

Adding to 4331320011305 its reverse (5031100231334), we get a palindrome (9362420242639).

The spelling of 4331320011305 in words is "four trillion, three hundred thirty-one billion, three hundred twenty million, eleven thousand, three hundred five".

Divisors: 1 5 7 35 49 245 343 1715 2525551027 12627755135 17678857189 88394285945 123752000323 618760001615 866264002261 4331320011305