Base | Representation |
---|---|
bin | 111111000001110110110… |
… | …010100110101000101001 |
3 | 120100001220010202011010222 |
4 | 333001312302212220221 |
5 | 1031431020410330210 |
6 | 13113440403415425 |
7 | 624633101432000 |
oct | 77016662465051 |
9 | 16301803664128 |
10 | 4331320011305 |
11 | 141a9a2257a31 |
12 | 59b532384575 |
13 | 2555986129c1 |
14 | 10d8cbd39c37 |
15 | 77a030d7655 |
hex | 3f076ca6a29 |
4331320011305 has 16 divisors (see below), whose sum is σ = 6061322467200. Its totient is φ = 2970048006576.
The previous prime is 4331320011269. The next prime is 4331320011313. The reversal of 4331320011305 is 5031100231334.
It is a de Polignac number, because none of the positive numbers 2k-4331320011305 is a prime.
It is a super-2 number, since 2×43313200113052 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1262773799 + ... + 1262777228.
It is an arithmetic number, because the mean of its divisors is an integer number (378832654200).
Almost surely, 24331320011305 is an apocalyptic number.
It is an amenable number.
4331320011305 is a deficient number, since it is larger than the sum of its proper divisors (1730002455895).
4331320011305 is an equidigital number, since it uses as much as digits as its factorization.
4331320011305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2525551053 (or 2525551039 counting only the distinct ones).
The product of its (nonzero) digits is 3240, while the sum is 26.
Adding to 4331320011305 its reverse (5031100231334), we get a palindrome (9362420242639).
The spelling of 4331320011305 in words is "four trillion, three hundred thirty-one billion, three hundred twenty million, eleven thousand, three hundred five".
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