4331414013011 has 4 divisors (see below), whose sum is σ = 4331435762592. Its totient is φ = 4331392263432.

The previous prime is 4331414013007. The next prime is 4331414013079. The reversal of 4331414013011 is 1103104141334.

4331414013011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4331414013011 - 2² = 4331414013007 is a prime.

It is a super-2 number, since 2×4331414013011² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4331114013011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10573280 + ... + 10975293.

It is an arithmetic number, because the mean of its divisors is an integer number (1082858940648).

Almost surely, 2^{4331414013011} is an apocalyptic number.

4331414013011 is a deficient number, since it is larger than the sum of its proper divisors (21749581).

4331414013011 is a wasteful number, since it uses less digits than its factorization.

4331414013011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21749580.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 4331414013011 its reverse (1103104141334), we get a palindrome (5434518154345).

The spelling of 4331414013011 in words is "four trillion, three hundred thirty-one billion, four hundred fourteen million, thirteen thousand, eleven".