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4331440001043 = 322309208432703
BaseRepresentation
bin111111000001111101111…
…100010101000000010011
3120100002012111112021010100
4333001331330111000103
51031431242120013133
613113500331303443
7624636056351211
oct77017574250023
916302174467110
104331440001043
11141aa53a62001
1259b5665aab83
132555b743504c
1410d8ddc51cb1
1577a0d8d9e13
hex3f07df15013

4331440001043 has 12 divisors (see below), whose sum is σ = 6259234101120. Its totient is φ = 2886376057296.

The previous prime is 4331440001027. The next prime is 4331440001081. The reversal of 4331440001043 is 3401000441334.

It is not a de Polignac number, because 4331440001043 - 24 = 4331440001027 is a prime.

It is a super-2 number, since 2×43314400010432 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4331440000998 and 4331440001016.

It is not an unprimeable number, because it can be changed into a prime (4331440001023) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 104195571 + ... + 104237132.

It is an arithmetic number, because the mean of its divisors is an integer number (521602841760).

Almost surely, 24331440001043 is an apocalyptic number.

4331440001043 is a deficient number, since it is larger than the sum of its proper divisors (1927794100077).

4331440001043 is a wasteful number, since it uses less digits than its factorization.

4331440001043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 208435018 (or 208435015 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 4331440001043 its reverse (3401000441334), we get a palindrome (7732440442377).

The spelling of 4331440001043 in words is "four trillion, three hundred thirty-one billion, four hundred forty million, one thousand, forty-three".

Divisors: 1 3 9 2309 6927 20781 208432703 625298109 1875894327 481271111227 1443813333681 4331440001043