Base | Representation |
---|---|
bin | 1100100110111100000… |
… | …00001100110101010001 |
3 | 1112102012221100111022102 |
4 | 12103132000030311101 |
5 | 24044214124332423 |
6 | 531004044250145 |
7 | 43204425332234 |
oct | 6233600146521 |
9 | 1472187314272 |
10 | 433221324113 |
11 | 157801163966 |
12 | 6bb64b40955 |
13 | 31b111c9c86 |
14 | 16d7a38741b |
15 | b408233c28 |
hex | 64de00cd51 |
433221324113 has 8 divisors (see below), whose sum is σ = 454775804160. Its totient is φ = 412140569040.
The previous prime is 433221324101. The next prime is 433221324127. The reversal of 433221324113 is 311423122334.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-433221324113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (433221324143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 118429370 + ... + 118433027.
It is an arithmetic number, because the mean of its divisors is an integer number (56846975520).
Almost surely, 2433221324113 is an apocalyptic number.
It is an amenable number.
433221324113 is a deficient number, since it is larger than the sum of its proper divisors (21554480047).
433221324113 is a wasteful number, since it uses less digits than its factorization.
433221324113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 236862487.
The product of its digits is 10368, while the sum is 29.
Adding to 433221324113 its reverse (311423122334), we get a palindrome (744644446447).
The spelling of 433221324113 in words is "four hundred thirty-three billion, two hundred twenty-one million, three hundred twenty-four thousand, one hundred thirteen".
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