Base | Representation |
---|---|
bin | 111111000010101101010… |
… | …001110010010110110001 |
3 | 120100011020211212111011012 |
4 | 333002231101302112301 |
5 | 1031434403420433231 |
6 | 13114111221000305 |
7 | 624664541510153 |
oct | 77025521622661 |
9 | 16304224774135 |
10 | 4332234155441 |
11 | 142032126aa55 |
12 | 59b748553095 |
13 | 2556b2b1c2aa |
14 | 10d9774d8ad3 |
15 | 77a584a9e2b |
hex | 3f0ad4725b1 |
4332234155441 has 4 divisors (see below), whose sum is σ = 4393251537984. Its totient is φ = 4271216772900.
The previous prime is 4332234155329. The next prime is 4332234155507. The reversal of 4332234155441 is 1445514322334.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4332234155441 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4332234154441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30508691165 + ... + 30508691306.
It is an arithmetic number, because the mean of its divisors is an integer number (1098312884496).
Almost surely, 24332234155441 is an apocalyptic number.
It is an amenable number.
4332234155441 is a deficient number, since it is larger than the sum of its proper divisors (61017382543).
4332234155441 is an equidigital number, since it uses as much as digits as its factorization.
4332234155441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61017382542.
The product of its digits is 691200, while the sum is 41.
Adding to 4332234155441 its reverse (1445514322334), we get a palindrome (5777748477775).
The spelling of 4332234155441 in words is "four trillion, three hundred thirty-two billion, two hundred thirty-four million, one hundred fifty-five thousand, four hundred forty-one".
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