4332253324041 has 6 divisors (see below), whose sum is σ = 6257699245850. Its totient is φ = 2888168882688.

The previous prime is 4332253323989. The next prime is 4332253324129. The reversal of 4332253324041 is 1404233522334.

4332253324041 is a `hidden beast` number, since 4 + 3 + 322 + 5 + 3 + 324 + 0 + 4 + 1 = 666.

It can be written as a sum of positive squares in only one way, i.e., 4325984010000 + 6269314041 = 2079900^2 + 79179^2 .

It is not a de Polignac number, because 4332253324041 - 2⁹ = 4332253323529 is a prime.

It is a super-3 number, since 3×4332253324041³ (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4332253323987 and 4332253324005.

It is not an unprimeable number, because it can be changed into a prime (4332253324241) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 240680740216 + ... + 240680740233.

Almost surely, 2^{4332253324041} is an apocalyptic number.

It is an amenable number.

4332253324041 is a deficient number, since it is larger than the sum of its proper divisors (1925445921809).

4332253324041 is a wasteful number, since it uses less digits than its factorization.

4332253324041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 481361480455 (or 481361480452 counting only the distinct ones).

The product of its (nonzero) digits is 207360, while the sum is 36.

Adding to 4332253324041 its reverse (1404233522334), we get a palindrome (5736486846375).

The spelling of 4332253324041 in words is "four trillion, three hundred thirty-two billion, two hundred fifty-three million, three hundred twenty-four thousand, forty-one".