Base | Representation |
---|---|
bin | 111111000011110101001… |
… | …111001000101111010001 |
3 | 120100021100222112220010022 |
4 | 333003311033020233101 |
5 | 1031444342000421431 |
6 | 13114431104513225 |
7 | 625036501213463 |
oct | 77036517105721 |
9 | 16307328486108 |
10 | 4333441420241 |
11 | 142089078895a |
12 | 59ba2491b815 |
13 | 255845c8836b |
14 | 10da4d99a133 |
15 | 77ac947d07b |
hex | 3f0f53c8bd1 |
4333441420241 has 8 divisors (see below), whose sum is σ = 4475454298368. Its totient is φ = 4191567570000.
The previous prime is 4333441420183. The next prime is 4333441420279. The reversal of 4333441420241 is 1420241443334.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4333441420241 - 218 = 4333441158097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4333441420291) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34693610 + ... + 34818291.
It is an arithmetic number, because the mean of its divisors is an integer number (559431787296).
Almost surely, 24333441420241 is an apocalyptic number.
It is an amenable number.
4333441420241 is a deficient number, since it is larger than the sum of its proper divisors (142012878127).
4333441420241 is a wasteful number, since it uses less digits than its factorization.
4333441420241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69513943.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 4333441420241 its reverse (1420241443334), we get a palindrome (5753682863575).
The spelling of 4333441420241 in words is "four trillion, three hundred thirty-three billion, four hundred forty-one million, four hundred twenty thousand, two hundred forty-one".
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