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4334404322121 = 33003314810697
BaseRepresentation
bin111111000100101110101…
…000010100001101001001
3120100100212002102101011220
4333010232220110031021
51032003330001301441
613115110423112253
7625102402563546
oct77045650241511
916310762371156
104334404322121
111421235273335
125a00532a2689
1325596a6067a3
1410db0180bbcd
1577b33c82466
hex3f12ea14349

4334404322121 has 8 divisors (see below), whose sum is σ = 5779226206944. Its totient is φ = 2889592659360.

The previous prime is 4334404322047. The next prime is 4334404322147. The reversal of 4334404322121 is 1212234044334.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 4334404322121 - 213 = 4334404313929 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4334404392121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1504356 + ... + 3306341.

It is an arithmetic number, because the mean of its divisors is an integer number (722403275868).

Almost surely, 24334404322121 is an apocalyptic number.

It is an amenable number.

4334404322121 is a deficient number, since it is larger than the sum of its proper divisors (1444821884823).

4334404322121 is a wasteful number, since it uses less digits than its factorization.

4334404322121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5111031.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 4334404322121 its reverse (1212234044334), we get a palindrome (5546638366455).

The spelling of 4334404322121 in words is "four trillion, three hundred thirty-four billion, four hundred four million, three hundred twenty-two thousand, one hundred twenty-one".

Divisors: 1 3 300331 900993 4810697 14432091 1444801440707 4334404322121