Base | Representation |
---|---|
bin | 1100101000011011011… |
… | …00101011100001011001 |
3 | 1112111021201001022112011 |
4 | 12110031230223201121 |
5 | 24102334001411210 |
6 | 531215311145521 |
7 | 43233312664312 |
oct | 6241554534131 |
9 | 1474251038464 |
10 | 434021513305 |
11 | 158081913946 |
12 | 70148b152a1 |
13 | 31c0ac17cc3 |
14 | 17014761609 |
15 | b4535e6d8a |
hex | 650db2b859 |
434021513305 has 4 divisors (see below), whose sum is σ = 520825815972. Its totient is φ = 347217210640.
The previous prime is 434021513281. The next prime is 434021513311. The reversal of 434021513305 is 503315120434.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 131931674176 + 302089839129 = 363224^2 + 549627^2 .
It is a de Polignac number, because none of the positive numbers 2k-434021513305 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43402151326 + ... + 43402151335.
It is an arithmetic number, because the mean of its divisors is an integer number (130206453993).
Almost surely, 2434021513305 is an apocalyptic number.
It is an amenable number.
434021513305 is a deficient number, since it is larger than the sum of its proper divisors (86804302667).
434021513305 is an equidigital number, since it uses as much as digits as its factorization.
434021513305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 86804302666.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 434021513305 its reverse (503315120434), we get a palindrome (937336633739).
The spelling of 434021513305 in words is "four hundred thirty-four billion, twenty-one million, five hundred thirteen thousand, three hundred five".
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