Search a number
-
+
4340255311131 = 33134622210129
BaseRepresentation
bin111111001010001011011…
…000000100010100011011
3120100220221212002102012120
4333022023120010110123
51032102320324424011
613121515154112323
7625400400301545
oct77121330042433
916326855072176
104340255311131
111423767a77a43
125a120687b6a3
1325639085b86c
141100d890c695
1577d77783a06
hex3f28b60451b

4340255311131 has 8 divisors (see below), whose sum is σ = 5805495923280. Its totient is φ = 2884259119872.

The previous prime is 4340255311129. The next prime is 4340255311151. The reversal of 4340255311131 is 1311135520434.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 4340255311131 - 21 = 4340255311129 is a prime.

It is a super-2 number, since 2×43402553111312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4340255311092 and 4340255311101.

It is not an unprimeable number, because it can be changed into a prime (4340255311151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2311104126 + ... + 2311106003.

It is an arithmetic number, because the mean of its divisors is an integer number (725686990410).

Almost surely, 24340255311131 is an apocalyptic number.

4340255311131 is a deficient number, since it is larger than the sum of its proper divisors (1465240612149).

4340255311131 is a wasteful number, since it uses less digits than its factorization.

4340255311131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4622210445.

The product of its (nonzero) digits is 21600, while the sum is 33.

The spelling of 4340255311131 in words is "four trillion, three hundred forty billion, two hundred fifty-five million, three hundred eleven thousand, one hundred thirty-one".

Divisors: 1 3 313 939 4622210129 13866630387 1446751770377 4340255311131