Base | Representation |
---|---|
bin | 111111001010010110101… |
… | …000101111100101000001 |
3 | 120100221110000120120220211 |
4 | 333022112220233211001 |
5 | 1032103212210411001 |
6 | 13121550023234121 |
7 | 625405153143343 |
oct | 77122650574501 |
9 | 16327400516824 |
10 | 4340444232001 |
11 | 1423854682a99 |
12 | 5a1259ba8941 |
13 | 2563c0a37067 |
14 | 110115a49293 |
15 | 77d89150351 |
hex | 3f296a2f941 |
4340444232001 has 16 divisors (see below), whose sum is σ = 4368248801280. Its totient is φ = 4312696115520.
The previous prime is 4340444231999. The next prime is 4340444232043. The reversal of 4340444232001 is 1002324440434.
It is a cyclic number.
It is not a de Polignac number, because 4340444232001 - 21 = 4340444231999 is a prime.
It is a super-2 number, since 2×43404442320012 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4340444232071) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 912047260 + ... + 912052018.
It is an arithmetic number, because the mean of its divisors is an integer number (273015550080).
Almost surely, 24340444232001 is an apocalyptic number.
It is an amenable number.
4340444232001 is a deficient number, since it is larger than the sum of its proper divisors (27804569279).
4340444232001 is a wasteful number, since it uses less digits than its factorization.
4340444232001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9504.
The product of its (nonzero) digits is 36864, while the sum is 31.
Adding to 4340444232001 its reverse (1002324440434), we get a palindrome (5342768672435).
The spelling of 4340444232001 in words is "four trillion, three hundred forty billion, four hundred forty-four million, two hundred thirty-two thousand, one".
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