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434100131011 = 6761631051291
BaseRepresentation
bin1100101000100100110…
…00100101010011000011
31112111111011222111202001
412110102120211103003
524103014113143021
6531231200204431
743235256142411
oct6242230452303
91474434874661
10434100131011
11158112230558
127016b309717
1331c212b3161
1417020d882b1
15b45a476091
hex65126254c3

434100131011 has 8 divisors (see below), whose sum is σ = 440651144384. Its totient is φ = 427551232680.

The previous prime is 434100130987. The next prime is 434100131029. The reversal of 434100131011 is 110131001434.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 434100131011 - 219 = 434099606723 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 434100131011.

It is not an unprimeable number, because it can be changed into a prime (434100131111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 112725 + ... + 938566.

It is an arithmetic number, because the mean of its divisors is an integer number (55081393048).

Almost surely, 2434100131011 is an apocalyptic number.

434100131011 is a deficient number, since it is larger than the sum of its proper divisors (6551013373).

434100131011 is a wasteful number, since it uses less digits than its factorization.

434100131011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1057521.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 434100131011 its reverse (110131001434), we get a palindrome (544231132445).

The spelling of 434100131011 in words is "four hundred thirty-four billion, one hundred million, one hundred thirty-one thousand, eleven".

Divisors: 1 67 6163 412921 1051291 70436497 6479106433 434100131011