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4341244130403 = 31499711955549
BaseRepresentation
bin111111001011000110010…
…100000111010001100011
3120101000111202201122020120
4333023012110013101203
51032111331444133103
613122201240011323
7625434035154555
oct77130624072143
916330452648216
104341244130403
111424125154554
125a1441a60b43
132564ba68291b
1411018dd894d5
1577dd44a7253
hex3f2c6507463

4341244130403 has 8 divisors (see below), whose sum is σ = 5827173330000. Its totient is φ = 2874738842208.

The previous prime is 4341244130359. The next prime is 4341244130449. The reversal of 4341244130403 is 3040314421434.

4341244130403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 4341244130403 - 217 = 4341243999331 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4341244130203) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4855977328 + ... + 4855978221.

It is an arithmetic number, because the mean of its divisors is an integer number (728396666250).

Almost surely, 24341244130403 is an apocalyptic number.

4341244130403 is a deficient number, since it is larger than the sum of its proper divisors (1485929199597).

4341244130403 is a wasteful number, since it uses less digits than its factorization.

4341244130403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9711955701.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 4341244130403 its reverse (3040314421434), we get a palindrome (7381558551837).

The spelling of 4341244130403 in words is "four trillion, three hundred forty-one billion, two hundred forty-four million, one hundred thirty thousand, four hundred three".

Divisors: 1 3 149 447 9711955549 29135866647 1447081376801 4341244130403