Base | Representation |
---|---|
bin | 1100101000101000111… |
… | …11101101010000011011 |
3 | 1112111120122122010122110 |
4 | 12110110133231100123 |
5 | 24103102200144201 |
6 | 531234503323403 |
7 | 43236166212564 |
oct | 6242437552033 |
9 | 1474518563573 |
10 | 434135553051 |
11 | 158130224672 |
12 | 7017b150563 |
13 | 31c28736045 |
14 | 1702596916b |
15 | b45d6216d6 |
hex | 65147ed41b |
434135553051 has 16 divisors (see below), whose sum is σ = 580563371520. Its totient is φ = 288566158560.
The previous prime is 434135553031. The next prime is 434135553119. The reversal of 434135553051 is 150355531434.
It is not a de Polignac number, because 434135553051 - 215 = 434135520283 is a prime.
It is not an unprimeable number, because it can be changed into a prime (434135553001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4041406 + ... + 4147436.
It is an arithmetic number, because the mean of its divisors is an integer number (36285210720).
Almost surely, 2434135553051 is an apocalyptic number.
434135553051 is a deficient number, since it is larger than the sum of its proper divisors (146427818469).
434135553051 is a wasteful number, since it uses less digits than its factorization.
434135553051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110066.
The product of its (nonzero) digits is 270000, while the sum is 39.
The spelling of 434135553051 in words is "four hundred thirty-four billion, one hundred thirty-five million, five hundred fifty-three thousand, fifty-one".
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