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43420344452113 = 360712037799959
BaseRepresentation
bin10011101111101100101100…
…01101010000010000010001
312200201221111110102220110211
421313312112031100100101
521142344331134431423
6232203010400124121
712101005420145236
oct1167662615202021
9180657443386424
1043420344452113
1112920512528132
124a531a1606641
131b2c6a05a3535
14aa17ad4c178d
155046e1e6510d
hex277d96350411

43420344452113 has 4 divisors (see below), whose sum is σ = 43432382255680. Its totient is φ = 43408306648548.

The previous prime is 43420344452087. The next prime is 43420344452137. The reversal of 43420344452113 is 31125444302434.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43420344452113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43420344455113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6018896373 + ... + 6018903586.

It is an arithmetic number, because the mean of its divisors is an integer number (10858095563920).

Almost surely, 243420344452113 is an apocalyptic number.

It is an amenable number.

43420344452113 is a deficient number, since it is larger than the sum of its proper divisors (12037803567).

43420344452113 is a wasteful number, since it uses less digits than its factorization.

43420344452113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12037803566.

The product of its (nonzero) digits is 552960, while the sum is 40.

Adding to 43420344452113 its reverse (31125444302434), we get a palindrome (74545788754547).

The spelling of 43420344452113 in words is "forty-three trillion, four hundred twenty billion, three hundred forty-four million, four hundred fifty-two thousand, one hundred thirteen".

Divisors: 1 3607 12037799959 43420344452113