Base | Representation |
---|---|
bin | 1100101000110100011… |
… | …00100111010001101001 |
3 | 1112111211022122001211122 |
4 | 12110122030213101221 |
5 | 24103301142223423 |
6 | 531252201505025 |
7 | 43241440252220 |
oct | 6243214472151 |
9 | 1474738561748 |
10 | 434231211113 |
11 | 15817a21aa17 |
12 | 701a71a2175 |
13 | 31c424b944b |
14 | 17034549cb7 |
15 | b466c198c8 |
hex | 651a327469 |
434231211113 has 8 divisors (see below), whose sum is σ = 512272765440. Its totient is φ = 360191787840.
The previous prime is 434231211097. The next prime is 434231211119. The reversal of 434231211113 is 311112132434.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 434231211113 - 24 = 434231211097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (434231211119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1000532528 + ... + 1000532961.
It is an arithmetic number, because the mean of its divisors is an integer number (64034095680).
Almost surely, 2434231211113 is an apocalyptic number.
It is an amenable number.
434231211113 is a deficient number, since it is larger than the sum of its proper divisors (78041554327).
434231211113 is a wasteful number, since it uses less digits than its factorization.
434231211113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2001065527.
The product of its digits is 1728, while the sum is 26.
Adding to 434231211113 its reverse (311112132434), we get a palindrome (745343343547).
The spelling of 434231211113 in words is "four hundred thirty-four billion, two hundred thirty-one million, two hundred eleven thousand, one hundred thirteen".
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