Base | Representation |
---|---|
bin | 111111001101000010010… |
… | …010101100000001001001 |
3 | 120101012212201121122012120 |
4 | 333031002102230001021 |
5 | 1032130111434201101 |
6 | 13123143501401453 |
7 | 625536422655453 |
oct | 77150222540111 |
9 | 16335781548176 |
10 | 4343324131401 |
11 | 1424aa2273042 |
12 | 5a1922569289 |
13 | 25675c58a948 |
14 | 11030a30b2d3 |
15 | 77ea6dbdb36 |
hex | 3f3424ac049 |
4343324131401 has 16 divisors (see below), whose sum is σ = 5889167890560. Its totient is φ = 2846565429120.
The previous prime is 4343324131397. The next prime is 4343324131403. The reversal of 4343324131401 is 1041314233434.
It is not a de Polignac number, because 4343324131401 - 22 = 4343324131397 is a prime.
It is a super-2 number, since 2×43433241314012 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4343324131403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5971740 + ... + 6659453.
It is an arithmetic number, because the mean of its divisors is an integer number (368072993160).
Almost surely, 24343324131401 is an apocalyptic number.
It is an amenable number.
4343324131401 is a deficient number, since it is larger than the sum of its proper divisors (1545843759159).
4343324131401 is a wasteful number, since it uses less digits than its factorization.
4343324131401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12633136.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 4343324131401 its reverse (1041314233434), we get a palindrome (5384638364835).
The spelling of 4343324131401 in words is "four trillion, three hundred forty-three billion, three hundred twenty-four million, one hundred thirty-one thousand, four hundred one".
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