Base | Representation |
---|---|
bin | 111111001101000111011… |
… | …010011010001001100001 |
3 | 120101020002201021022121220 |
4 | 333031013122122021201 |
5 | 1032130300432311231 |
6 | 13123200211005253 |
7 | 625541515125162 |
oct | 77150732321141 |
9 | 16336081238556 |
10 | 4343410041441 |
11 | 1425036810579 |
12 | 5a1947299829 |
13 | 25677430a0a3 |
14 | 1103178b1769 |
15 | 77eae6dd896 |
hex | 3f34769a261 |
4343410041441 has 4 divisors (see below), whose sum is σ = 5791213388592. Its totient is φ = 2895606694292.
The previous prime is 4343410041431. The next prime is 4343410041463. The reversal of 4343410041441 is 1441400143434.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4343410041441 - 211 = 4343410039393 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4343410041401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 723901673571 + ... + 723901673576.
It is an arithmetic number, because the mean of its divisors is an integer number (1447803347148).
Almost surely, 24343410041441 is an apocalyptic number.
It is an amenable number.
4343410041441 is a deficient number, since it is larger than the sum of its proper divisors (1447803347151).
4343410041441 is a wasteful number, since it uses less digits than its factorization.
4343410041441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1447803347150.
The product of its (nonzero) digits is 36864, while the sum is 33.
Adding to 4343410041441 its reverse (1441400143434), we get a palindrome (5784810184875).
The spelling of 4343410041441 in words is "four trillion, three hundred forty-three billion, four hundred ten million, forty-one thousand, four hundred forty-one".
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