Base | Representation |
---|---|
bin | 10011110000001000101001… |
… | …01110101010001001001011 |
3 | 12200210101020100212100210122 |
4 | 21320010110232222021023 |
5 | 21143121100110240021 |
6 | 232213531504533455 |
7 | 12102046341426641 |
oct | 1170042456521113 |
9 | 180711210770718 |
10 | 43435352040011 |
11 | 12926913962038 |
12 | 4a5608b62128b |
13 | 1b30c22878269 |
14 | aa23d471d191 |
15 | 504cbe777bab |
hex | 278114baa24b |
43435352040011 has 8 divisors (see below), whose sum is σ = 45325878328320. Its totient is φ = 41544995145192.
The previous prime is 43435352040007. The next prime is 43435352040023. The reversal of 43435352040011 is 11004025353434.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 43435352040011 - 22 = 43435352040007 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43435352042011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41824241 + ... + 42850178.
It is an arithmetic number, because the mean of its divisors is an integer number (5665734791040).
Almost surely, 243435352040011 is an apocalyptic number.
43435352040011 is a deficient number, since it is larger than the sum of its proper divisors (1890526288309).
43435352040011 is a wasteful number, since it uses less digits than its factorization.
43435352040011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84696745.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 43435352040011 its reverse (11004025353434), we get a palindrome (54439377393445).
The spelling of 43435352040011 in words is "forty-three trillion, four hundred thirty-five billion, three hundred fifty-two million, forty thousand, eleven".
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