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434535203121 = 3144845067707
BaseRepresentation
bin1100101001011000101…
…00010000000100110001
31112112121111122110110220
412110230110100010301
524104412002444441
6531342301243253
743252121166255
oct6245424200461
91475544573426
10434535203121
11158315880688
1270270b63529
1331c90484286
1417062a7c265
15b483766466
hex652c510131

434535203121 has 4 divisors (see below), whose sum is σ = 579380270832. Its totient is φ = 289690135412.

The previous prime is 434535203107. The next prime is 434535203143. The reversal of 434535203121 is 121302535434.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 434535203121 - 26 = 434535203057 is a prime.

It is not an unprimeable number, because it can be changed into a prime (434535203171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72422533851 + ... + 72422533856.

It is an arithmetic number, because the mean of its divisors is an integer number (144845067708).

Almost surely, 2434535203121 is an apocalyptic number.

It is an amenable number.

434535203121 is a deficient number, since it is larger than the sum of its proper divisors (144845067711).

434535203121 is a wasteful number, since it uses less digits than its factorization.

434535203121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 144845067710.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 434535203121 its reverse (121302535434), we get a palindrome (555837738555).

The spelling of 434535203121 in words is "four hundred thirty-four billion, five hundred thirty-five million, two hundred three thousand, one hundred twenty-one".

Divisors: 1 3 144845067707 434535203121