Base | Representation |
---|---|
bin | 111111001111000000100… |
… | …101101011101101110001 |
3 | 120101102100101201100112000 |
4 | 333033000211223231301 |
5 | 1032143431404240423 |
6 | 13124134033124213 |
7 | 625643062255050 |
oct | 77170045535561 |
9 | 16342311640460 |
10 | 4345443040113 |
11 | 142598a34656a |
12 | 5a22140b9669 |
13 | 256a09569296 |
14 | 11046b8ba397 |
15 | 7807ce1d843 |
hex | 3f3c096bb71 |
4345443040113 has 128 divisors (see below), whose sum is σ = 7777296691200. Its totient is φ = 2342503328256.
The previous prime is 4345443040091. The next prime is 4345443040121. The reversal of 4345443040113 is 3110403445434.
4345443040113 is a `hidden beast` number, since 4 + 34 + 544 + 30 + 40 + 1 + 13 = 666.
It is a de Polignac number, because none of the positive numbers 2k-4345443040113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4345443040163) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1963597195 + ... + 1963599407.
It is an arithmetic number, because the mean of its divisors is an integer number (60760130400).
Almost surely, 24345443040113 is an apocalyptic number.
It is an amenable number.
4345443040113 is a deficient number, since it is larger than the sum of its proper divisors (3431853651087).
4345443040113 is a wasteful number, since it uses less digits than its factorization.
4345443040113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4308 (or 4302 counting only the distinct ones).
The product of its (nonzero) digits is 138240, while the sum is 36.
Adding to 4345443040113 its reverse (3110403445434), we get a palindrome (7455846485547).
The spelling of 4345443040113 in words is "four trillion, three hundred forty-five billion, four hundred forty-three million, forty thousand, one hundred thirteen".
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