Base | Representation |
---|---|
bin | 111111010011100010110… |
… | …111100010100110110001 |
3 | 120101212220210121202000011 |
4 | 333103202313202212301 |
5 | 1032233420124122113 |
6 | 13130301203454521 |
7 | 626204546230225 |
oct | 77234267424661 |
9 | 16355823552004 |
10 | 4350313114033 |
11 | 1427a59382147 |
12 | 5a3153087441 |
13 | 257304506c23 |
14 | 1107b05da785 |
15 | 7826575d63d |
hex | 3f4e2de29b1 |
4350313114033 has 16 divisors (see below), whose sum is σ = 4703294808000. Its totient is φ = 4009745218752.
The previous prime is 4350313114031. The next prime is 4350313114039. The reversal of 4350313114033 is 3304113130534.
4350313114033 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 4350313114033 - 21 = 4350313114031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4350313113986 and 4350313114004.
It is not an unprimeable number, because it can be changed into a prime (4350313114031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13698438 + ... + 14012416.
It is an arithmetic number, because the mean of its divisors is an integer number (293955925500).
Almost surely, 24350313114033 is an apocalyptic number.
It is an amenable number.
4350313114033 is a deficient number, since it is larger than the sum of its proper divisors (352981693967).
4350313114033 is a wasteful number, since it uses less digits than its factorization.
4350313114033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 333744.
The product of its (nonzero) digits is 19440, while the sum is 31.
Adding to 4350313114033 its reverse (3304113130534), we get a palindrome (7654426244567).
The spelling of 4350313114033 in words is "four trillion, three hundred fifty billion, three hundred thirteen million, one hundred fourteen thousand, thirty-three".
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