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43522226131 = 349124705519
BaseRepresentation
bin101000100010001000…
…000111011111010011
311011100010202011102011
4220202020013133103
51203113142214011
631554400203351
73100343550436
oct504210073723
9134303664364
1043522226131
111750418672a
128527609557
134147a01637
14216c2b381d
1511ead34621
hexa222077d3

43522226131 has 4 divisors (see below), whose sum is σ = 43646932000. Its totient is φ = 43397520264.

The previous prime is 43522226129. The next prime is 43522226141. The reversal of 43522226131 is 13162222534.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 43522226131 - 21 = 43522226129 is a prime.

It is a super-2 number, since 2×435222261312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43522226093 and 43522226102.

It is not an unprimeable number, because it can be changed into a prime (43522226141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62352411 + ... + 62353108.

It is an arithmetic number, because the mean of its divisors is an integer number (10911733000).

Almost surely, 243522226131 is an apocalyptic number.

43522226131 is a deficient number, since it is larger than the sum of its proper divisors (124705869).

43522226131 is a wasteful number, since it uses less digits than its factorization.

43522226131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 124705868.

The product of its digits is 17280, while the sum is 31.

Adding to 43522226131 its reverse (13162222534), we get a palindrome (56684448665).

The spelling of 43522226131 in words is "forty-three billion, five hundred twenty-two million, two hundred twenty-six thousand, one hundred thirty-one".

Divisors: 1 349 124705519 43522226131