Base | Representation |
---|---|
bin | 101000100010001011… |
… | …000111001000110001 |
3 | 11011100012020001012212 |
4 | 220202023013020301 |
5 | 1203113342323441 |
6 | 31554425101505 |
7 | 3100353330152 |
oct | 504213071061 |
9 | 134305201185 |
10 | 43523011121 |
11 | 17504672487 |
12 | 8527927895 |
13 | 4147c17a25 |
14 | 216c439929 |
15 | 11eae3beeb |
hex | a222c7231 |
43523011121 has 4 divisors (see below), whose sum is σ = 43526416500. Its totient is φ = 43519605744.
The previous prime is 43523011109. The next prime is 43523011151. The reversal of 43523011121 is 12111032534.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 19983780496 + 23539230625 = 141364^2 + 153425^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43523011121 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43523011151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1683446 + ... + 1709103.
It is an arithmetic number, because the mean of its divisors is an integer number (10881604125).
Almost surely, 243523011121 is an apocalyptic number.
It is an amenable number.
43523011121 is a deficient number, since it is larger than the sum of its proper divisors (3405379).
43523011121 is a wasteful number, since it uses less digits than its factorization.
43523011121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3405378.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 43523011121 its reverse (12111032534), we get a palindrome (55634043655).
The spelling of 43523011121 in words is "forty-three billion, five hundred twenty-three million, eleven thousand, one hundred twenty-one".
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