Base | Representation |
---|---|
bin | 101000100011010111… |
… | …110111010001101001 |
3 | 11011101121002020211111 |
4 | 220203113313101221 |
5 | 1203134020144431 |
6 | 32000424230321 |
7 | 3101016336331 |
oct | 504327672151 |
9 | 134347066744 |
10 | 43543131241 |
11 | 17514a64a85 |
12 | 853260b3a1 |
13 | 414c140a1c |
14 | 2170d960c1 |
15 | 11ecab37b1 |
hex | a235f7469 |
43543131241 has 4 divisors (see below), whose sum is σ = 43965880192. Its totient is φ = 43120382292.
The previous prime is 43543131209. The next prime is 43543131257. The reversal of 43543131241 is 14213134534.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 43543131241 - 25 = 43543131209 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43543131941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211374321 + ... + 211374526.
It is an arithmetic number, because the mean of its divisors is an integer number (10991470048).
Almost surely, 243543131241 is an apocalyptic number.
It is an amenable number.
43543131241 is a deficient number, since it is larger than the sum of its proper divisors (422748951).
43543131241 is a wasteful number, since it uses less digits than its factorization.
43543131241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 422748950.
The product of its digits is 17280, while the sum is 31.
Adding to 43543131241 its reverse (14213134534), we get a palindrome (57756265775).
The spelling of 43543131241 in words is "forty-three billion, five hundred forty-three million, one hundred thirty-one thousand, two hundred forty-one".
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