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4355224113113 = 31140491100423
BaseRepresentation
bin111111011000000111100…
…101100000111111011001
3120102100121001112100020222
4333120013211200333121
51032323444333104423
613132432355325425
7626440341102626
oct77300745407731
916370531470228
104355224113113
11142a049520475
125a40a38b0875
13257907aa3543
14110b1893134d
15784519843c8
hex3f607960fd9

4355224113113 has 4 divisors (see below), whose sum is σ = 4495715213568. Its totient is φ = 4214733012660.

The previous prime is 4355224113083. The next prime is 4355224113277. The reversal of 4355224113113 is 3113114225534.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4355224113113 - 26 = 4355224113049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4355224113613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70245550181 + ... + 70245550242.

It is an arithmetic number, because the mean of its divisors is an integer number (1123928803392).

Almost surely, 24355224113113 is an apocalyptic number.

It is an amenable number.

4355224113113 is a deficient number, since it is larger than the sum of its proper divisors (140491100455).

4355224113113 is a wasteful number, since it uses less digits than its factorization.

4355224113113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 140491100454.

The product of its digits is 43200, while the sum is 35.

Adding to 4355224113113 its reverse (3113114225534), we get a palindrome (7468338338647).

The spelling of 4355224113113 in words is "four trillion, three hundred fifty-five billion, two hundred twenty-four million, one hundred thirteen thousand, one hundred thirteen".

Divisors: 1 31 140491100423 4355224113113