Base | Representation |
---|---|
bin | 111111100000100110111… |
… | …111110101011111011001 |
3 | 120110020010102122021022222 |
4 | 333200212333311133121 |
5 | 1033001132301303423 |
6 | 13140541154553425 |
7 | 630212303521634 |
oct | 77404677653731 |
9 | 16406112567288 |
10 | 4364341041113 |
11 | 14329a7815409 |
12 | 5a5a08b98875 |
13 | 25872b8433b1 |
14 | 1113416a2c1b |
15 | 787d705b3c8 |
hex | 3f826ff57d9 |
4364341041113 has 8 divisors (see below), whose sum is σ = 4387741106688. Its totient is φ = 4341001208544.
The previous prime is 4364341041097. The next prime is 4364341041133. The reversal of 4364341041113 is 3111401434634.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4364341041113 - 24 = 4364341041097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4364341041133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14912945 + ... + 15202782.
It is an arithmetic number, because the mean of its divisors is an integer number (548467638336).
Almost surely, 24364341041113 is an apocalyptic number.
It is an amenable number.
4364341041113 is a deficient number, since it is larger than the sum of its proper divisors (23400065575).
4364341041113 is a wasteful number, since it uses less digits than its factorization.
4364341041113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30116503.
The product of its (nonzero) digits is 41472, while the sum is 35.
Adding to 4364341041113 its reverse (3111401434634), we get a palindrome (7475742475747).
The spelling of 4364341041113 in words is "four trillion, three hundred sixty-four billion, three hundred forty-one million, forty-one thousand, one hundred thirteen".
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