Base | Representation |
---|---|
bin | 111111100110111010101… |
… | …011100000000011011001 |
3 | 120110212121102121021112201 |
4 | 333212322223200003121 |
5 | 1033104020102040224 |
6 | 13144021212410201 |
7 | 630542162313463 |
oct | 77467253400331 |
9 | 16425542537481 |
10 | 4371113705689 |
11 | 1435862806565 |
12 | 5a7199176961 |
13 | 25926aa10b23 |
14 | 1117c4d63133 |
15 | 78a8191ba44 |
hex | 3f9baae00d9 |
4371113705689 has 4 divisors (see below), whose sum is σ = 4397288039424. Its totient is φ = 4344939371956.
The previous prime is 4371113705641. The next prime is 4371113705711. The reversal of 4371113705689 is 9865073111734.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4371113705689 - 219 = 4371113181401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4371113735689) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13087166617 + ... + 13087166950.
It is an arithmetic number, because the mean of its divisors is an integer number (1099322009856).
Almost surely, 24371113705689 is an apocalyptic number.
It is an amenable number.
4371113705689 is a deficient number, since it is larger than the sum of its proper divisors (26174333735).
4371113705689 is a wasteful number, since it uses less digits than its factorization.
4371113705689 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26174333734.
The product of its (nonzero) digits is 3810240, while the sum is 55.
The spelling of 4371113705689 in words is "four trillion, three hundred seventy-one billion, one hundred thirteen million, seven hundred five thousand, six hundred eighty-nine".
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